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Determine the equation of the circle graphed below

Determine The Equation Of The Circle Graphed Below class=

Sagot :

Corsaquix

Answer:

[tex](x-1)^2+(y-6)^2=16[/tex]

Step-by-step explanation:

The equation of a circle is given by [tex](x-h)^2+(y-k)^2=r^2[/tex], where [tex](h,k)[/tex] is the center of the circle and [tex]r[/tex] is the radius of the circle.

From the diagram, we can find the following:

  • the radius of the circle is 4
  • the center of the circle is located at (1,6)

Thus, we have:

[tex](x-1)^2+(y-6)^2=4^2,\\\boxed{(x-1)^2+(y-6)^2=16}[/tex]

anhtampham

Answer:

(x-1)^2 + (y-6)^2 = 16

Step-by-step explanation:

center = (1,6)

radius = 4

equation of a circle (x-h)^2+(y-k)^2=r^2

(x-1)^2 + (y-6)^2 = 16

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