Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Ask your questions and receive precise answers from experienced professionals across different disciplines. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Determine the equation of the circle graphed below

Determine The Equation Of The Circle Graphed Below class=

Sagot :

Answer:

[tex](x-1)^2+(y-6)^2=16[/tex]

Step-by-step explanation:

The equation of a circle is given by [tex](x-h)^2+(y-k)^2=r^2[/tex], where [tex](h,k)[/tex] is the center of the circle and [tex]r[/tex] is the radius of the circle.

From the diagram, we can find the following:

  • the radius of the circle is 4
  • the center of the circle is located at (1,6)

Thus, we have:

[tex](x-1)^2+(y-6)^2=4^2,\\\boxed{(x-1)^2+(y-6)^2=16}[/tex]

Answer:

(x-1)^2 + (y-6)^2 = 16

Step-by-step explanation:

center = (1,6)

radius = 4

equation of a circle (x-h)^2+(y-k)^2=r^2

(x-1)^2 + (y-6)^2 = 16