Answer:
Option D (y = 5/6x -12).
Step-by-step explanation:
Hey there!
The equation of the line which passes through the point (12,-2) is (y+2) = m2(x-12)………(i) [Using one point formula].
According to the question, the first line passes through point (12,6) and (0,-4).
So,
[tex]slope(m1) = \frac{y2 - y1}{x2 - x1} [/tex]
[tex]or \: m1 = \frac{ - 4 - 6}{0 - 12} [/tex]
[tex]or \: m1 = \frac{5}{6} [/tex]
Therefore, the slope of the line is 5/6.
Now as per the condition of parallel lines, m1 =m2 = 5/6.
So, keeping the value of m2 in equation (i), we get;
(y+2) = 5/6(x-12)
[tex]y + 2 = \frac{5}{6} x - 10[/tex]
or, y = 5/6x - 12.
Therefore, the required equation is y = 5/6 X - 12.
Hope it helps!
