Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A 1.513 g sample of KHP (C8H5O4K) is dissolved in 50.0 mL of DI water. When the KHP solution was titrated with NaOH, 14.8 mL was required to reach the phenolphthalien end point. Calculate the molarity of the NaOH solution

Sagot :

maacastrobr

Answer:

0.501 M

Explanation:

  • KHP + NaOH → NaKP + H₂O

First we convert 1.513 g of KHP into moles, using its molar mass:

  • 1.513 g ÷ 204.22 g/mol = 7.41x10⁻³ mol = 7.41 mmol

As 1 mol of KHP reacts with 1 mol of NaOH, in 14.8 mL of the NaOH solution there were 7.41 mmoles of NaOH.

With the above information in mind we can calculate the molarity of the NaOH solution:

  • 7.41 mmol / 14.8 mL = 0.501 M
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.