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Sagot :

A is the correct form
angstar4
Option 4: 84/2 over 121

sin^2x + cos^2x = 1
sin^2x + (7/11)^2 = 1
sin^2x + 49/121 = 1
sin^2x = 72/121
sinx = square root of 72/121
sinx = (6 root 2) / 11

sin2x = 2sinxcosx
sin2x = 2[(6 root 2)/11] (7/11)
sin2x = (2*6*7*root 2) / (11*11)
sin2x = 84 root 2 / 121 :)
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