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What is the equation of the line that passes through the points
(6,8) and (-10, – 7)?

Sagot :

Answer:

y=15/16x+19/8

Step-by-step explanation:

Hi there!

We are given the points (6,8) and (-10, -7) and we need to find the equation of the line

There are 3 ways to write the equation of the line, but the most common format is slope-intercept form, or y=mx+b form, where m is the slope and b is the y intercept

First, we need to find the slope

The formula for the slope calculated from two points is (y2-y1)/(x2-x1), where (x1, y1) and (x2,y2) are points

Our (x1,y1), and (x2,y2) are (6,8) and (-10, -7)

we can label their values to avoid confusion:

x1=6

y1=8

x2=-10

y2=-7

substitute into the formula

m=(-7-8)/(-10-6)

m=15/16

so the slope is 15/16

here's our equation so far:

y=15/16x+b

we need to solve for b

Because the line will pass through (6,8) and (-10,-7), we can substitute either one of them into the equation to solve for b

Let's take (6,8) as an example

Substitute x as 6 and y as 8

8=15/16(6)+b

Multiply

8=45/8+b

subtract

19/8=b

therefore, the equation of the line is:

y=15/16x+19/8

Hope this helps! :)