Answered

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What is the voltage drop across an alarm clock that is connected to a circuit with a current of 1.10A and a resistance of 90Ω?

Sagot :

Trancescient

V = 99 volts

Explanation:

The voltage drop can be calculated using Ohm's law:

V = IR

= (1.10 A)(90 Ω)

= 99 volts

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