Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

find the equation of the line that is perpendicluar to y=-2/3x and contains the point (4,-8)

Sagot :

jcherry99

Answer:

Step-by-step explanation:

The slope of two perpendiculars is

m1*m2 = - 1

m1 = - 2/3

-2/3 * m2 = -1                      Multiply both sides by -3/2

-3/2 * -2/3 * m2 = -1*-3/2

m2 = 3/2

So far what you have is

y = 3/2 x + b

x = 4

y = - 8

-8 = 3/2*4 + b

-8 = 6 + b           Subtract 6 from both sides

b = - 14

Complete line

y = 3/2 x  - 14

The red line is y = -2/3x

The blue line is y = 3/2x - 14

The point (4,-8) is marked for you

View image jcherry99
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.