Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Your Algebra 2 class has 20 students. 4 students are to be chosen at random for a project.

A. How many groups of four are possible?

B. You are in the Algebra 2 class with 3 other friends. What is the probability that the four of you are chosen?

Sagot :

Answer:

A. 5 groups

Step-by-step explanation:

You would use multiplication for this. just think what does 4 × _ = 20? well 5! since four times give is twenty.

Answer:

4845

.020639% (or 1/4845)

Step-by-step explanation:

For the first one we have to use combinations (because the order doesn't matter)

The formula is as follows:

for ACB

[tex]\frac{A!}{(A-B)!*B!}\\\\\frac{20!}{(20-4)!*4!}=4845[/tex]

2.

for probabilty the odds of an outcome is just: number of times the requirement is satisfied/total number of possibliites

we know that there are 4845 possbile groups and only one in which we get all of our friends so it's just

1/4845= .020639%

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.