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Answer: A balanced equation for the equilibrium reaction where the aqueous bicarbonate ion, [tex]HCO^{-}_{3}(aq)[/tex]; decomposes to form hydrogen ions, [tex]H^{+}(aq)[/tex] and carbonate ions, [tex]CO^{2-}_{3}[/tex] is [tex]HCO^{-}_{3} \rightleftharpoons H^{+}(aq) + CO^{2-}_{3}[/tex].
Explanation:
A balanced chemical equation is defined as the equation which contains same number of atoms on both reactant and product side.
Hence, balanced equation for the equilibrium reaction where the aqueous bicarbonate ion, [tex]HCO^{-}_{3}(aq)[/tex]; decomposes to form hydrogen ions, [tex]H^{+}(aq)[/tex] and carbonate ions, [tex]CO^{2-}_{3}[/tex] is as follows.
[tex]HCO^{-}_{3} \rightleftharpoons H^{+}(aq) + CO^{2-}_{3}[/tex]
Here, number of atoms present on reactant side are as follows.
- H = 1
- C = 1
- O = 3
Number of atoms present on product side are as follows.
- H = 1
- C = 1
- O = 3
Since, there are same number of atoms present on both reactant and product side. Therefore, this equation is balanced.
Thus, we can conclude that balanced equation for the equilibrium reaction where the aqueous bicarbonate ion, [tex]HCO^{-}_{3}(aq)[/tex]; decomposes to form hydrogen ions, [tex]H^{+}(aq)[/tex] and carbonate ions, [tex]CO^{2-}_{3}[/tex] is [tex]HCO^{-}_{3} \rightleftharpoons H^{+}(aq) + CO^{2-}_{3}[/tex].
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