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The roots of [tex]10x^2-14x+k[/tex] are sin a and cos a for some real value of a. Compute k.

Sagot :

ferrybukantoro

Answer:

10

Step-by-step explanation:

10x²-14x+k = 0

x1 = sin a

x2= cos a

x1+x2 ≤ 2

x1. x2 ≤ 1 => k/10 ≤ 1

k ≤ 10

so the value of k should be 10

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