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Use the diagram below to match the ratios below. B a A b sin B COS B tan B tan A COS A sin A​

Use The Diagram Below To Match The Ratios Below B A A B Sin B COS B Tan B Tan A COS A Sin A class=

Sagot :

MrRoyal

Answer:

See explanation

Step-by-step explanation:

Given

The attached triangle

Required

Complete the ratios

(a) sin B

[tex]\sin(B)[/tex] is calculated as:

[tex]\sin(B) = \frac{Opposite}{Hypotenuse}[/tex]

[tex]\sin(B) = \frac{b}{c}[/tex]

(b) cos B

[tex]\cos(B)[/tex] is calculated as:

[tex]\cos(B) = \frac{Adjacent}{Hypotenuse}[/tex]

[tex]\cos(B) = \frac{a}{c}[/tex]

(c) tan B

[tex]\tan(B)[/tex] is calculated as:

[tex]\tan(B) = \frac{Opposite}{Adjacent}[/tex]

[tex]\tan(B) = \frac{b}{a}[/tex]

(d) tan A

[tex]\tan(A)[/tex] is calculated as:

[tex]\tan(A)= \frac{Opposite}{Adjacent}[/tex]

[tex]\tan(A) = \frac{a}{b}[/tex]

(e) cos A

[tex]\cos(A)[/tex] is calculated as:

[tex]\cos(A) = \frac{Adjacent}{Hypotenuse}[/tex]

[tex]\cos(A) = \frac{b}{c}[/tex]

(f) sin A

[tex]\ain(B)[/tex] is calculated as:

[tex]\sin(B) = \frac{Opposite}{Adjacent}[/tex]

[tex]\sin(B) = \frac{a}{c}[/tex]

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