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Sagot :
Answer:
N2 +3 H2 → 2 NH3
so we have 2180 g of N2
or 2.80 g ÷ 28.02 g/mol = 0.100 mol
1 mol of N2 react with 3 moles of H2
Therefore 0.100 mol of N2 react with 0.3 moles of H2
0.300 mol X Molar mass (2.00 g/mol) = 0.600 g
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