hadeelalniamia
Answered

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please help me do this question I will really appreciate it

Please Help Me Do This Question I Will Really Appreciate It class=

Sagot :

bhadelsimron19

Answer:

Step-by-step explanation:

for JJ'

x1=-2  x2=3  y1=-2  y2=6

slope =y2-y1/x2-x1

=6-(-2)/3-(-2)

=6+2/3+2

=8/5

for KK'

x1=-8  x2=-3  y1=-4  y2=4

slope=y2-y1/x2-x1

=4-(-4)/-3-(-8)

=4+4/-3+8

=8/5

for LL'

x1=-6  x2=-1  y1=-6  y2=2

slope=y2-y1/x2-x1

=2-(-6)/-1-(-6)

=2+6/-1+6

=8/5

Goddessvenus

Answer:

Repeat with

(x₁, y₁ ) = L(- 6, - 6) and (x₂, y₂ ) = L'(- 1, 2)

LL' = \sqrt{(-1+6)^2+(2+6)^2}

(−1+6)

2

+(2+6)

2

= \sqrt{5^2+8^2}

5

2

+8

2

= \sqrt{25+64}

25+64

= \sqrt{89}

89

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