hadeelalniamia
Answered

Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

please help me do this question I will really appreciate it

Please Help Me Do This Question I Will Really Appreciate It class=

Sagot :

Answer:

all [tex]\sqrt{89}[/tex]

Step-by-step explanation:

Calculate the lengths using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = J(- 2, - 2) and (x₂, y₂ ) = J'(3, 6)

JJ' = [tex]\sqrt{(3+2)^2+(6+2)^2}[/tex] = [tex]\sqrt{5^2+8^2}[/tex] = [tex]\sqrt{25+64}[/tex] = [tex]\sqrt{89}[/tex]

Repeat with

(x₁, y₁ ) = K(- 8, - 4) and (x₂, y₂ ) = K'(- 3, 4)

KK' = [tex]\sqrt{(-3+8)^2+(4+4)^2}[/tex] = [tex]\sqrt{5^2+8^2}[/tex] = [tex]\sqrt{25+64}[/tex] = [tex]\sqrt{89}[/tex]

Repeat with

(x₁, y₁ ) = L(- 6, - 6) and (x₂, y₂ ) = L'(- 1, 2)

LL' = [tex]\sqrt{(-1+6)^2+(2+6)^2}[/tex] = [tex]\sqrt{5^2+8^2}[/tex] = [tex]\sqrt{25+64}[/tex] = [tex]\sqrt{89}[/tex]

Goddessvenus

Answer:

Repeat with

(x₁, y₁ ) = L(- 6, - 6) and (x₂, y₂ ) = L'(- 1, 2)

LL' = \sqrt{(-1+6)^2+(2+6)^2}

(−1+6)

2

+(2+6)

2

= \sqrt{5^2+8^2}

5

2

+8

2

= \sqrt{25+64}

25+64

= \sqrt{89}

89

Step-by-step explanation:

Repeat with

(x₁, y₁ ) = L(- 6, - 6) and (x₂, y₂ ) = L'(- 1, 2)

LL' = \sqrt{(-1+6)^2+(2+6)^2}

(−1+6)

2

+(2+6)

2

= \sqrt{5^2+8^2}

5

2

+8

2

= \sqrt{25+64}

25+64

= \sqrt{89}

89

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.