hadeelalniamia
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please help me do this question I will really appreciate it

Please Help Me Do This Question I Will Really Appreciate It class=

Sagot :

Answer:

all [tex]\sqrt{89}[/tex]

Step-by-step explanation:

Calculate the lengths using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = J(- 2, - 2) and (x₂, y₂ ) = J'(3, 6)

JJ' = [tex]\sqrt{(3+2)^2+(6+2)^2}[/tex] = [tex]\sqrt{5^2+8^2}[/tex] = [tex]\sqrt{25+64}[/tex] = [tex]\sqrt{89}[/tex]

Repeat with

(x₁, y₁ ) = K(- 8, - 4) and (x₂, y₂ ) = K'(- 3, 4)

KK' = [tex]\sqrt{(-3+8)^2+(4+4)^2}[/tex] = [tex]\sqrt{5^2+8^2}[/tex] = [tex]\sqrt{25+64}[/tex] = [tex]\sqrt{89}[/tex]

Repeat with

(x₁, y₁ ) = L(- 6, - 6) and (x₂, y₂ ) = L'(- 1, 2)

LL' = [tex]\sqrt{(-1+6)^2+(2+6)^2}[/tex] = [tex]\sqrt{5^2+8^2}[/tex] = [tex]\sqrt{25+64}[/tex] = [tex]\sqrt{89}[/tex]

Goddessvenus

Answer:

Repeat with

(x₁, y₁ ) = L(- 6, - 6) and (x₂, y₂ ) = L'(- 1, 2)

LL' = \sqrt{(-1+6)^2+(2+6)^2}

(−1+6)

2

+(2+6)

2

= \sqrt{5^2+8^2}

5

2

+8

2

= \sqrt{25+64}

25+64

= \sqrt{89}

89

Step-by-step explanation:

Repeat with

(x₁, y₁ ) = L(- 6, - 6) and (x₂, y₂ ) = L'(- 1, 2)

LL' = \sqrt{(-1+6)^2+(2+6)^2}

(−1+6)

2

+(2+6)

2

= \sqrt{5^2+8^2}

5

2

+8

2

= \sqrt{25+64}

25+64

= \sqrt{89}

89

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