Answered

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2. If x is directly proportional to y^3 and x=32 when y=2, i) Find an equation
connecting x and y, ii) Find the value of x when y=6, iii) Calculate the value
of y when x=108. *

Sagot :

mercy17

Answer:

(i)

[tex] x \alpha y {3} \\ \frac{x}{y {3} } = k[/tex]

(ii)

[tex] \frac{x}{y {3}^{} } = \frac{x}{y {3}^{} } \\ \frac{32}{ {2}^{3} } = \frac{x}{6 {}^{3} } \\ \frac{32}{8} = \frac{x}{216} \\ x = 864[/tex]

(iii)

[tex] \frac{32}{8} = \frac{108}{y {}^{3} } \\ {y}^{3 } = 27 \\ y = \sqrt[3]{27 } \\ y = 3[/tex]

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