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Ethyl ethanoate undergoes following reaction [on the picture]

Equal amounts of ethanoic acid and ethanol were mixed together and allowed to reach equilibrium.

At equilibrium, the concentrations of both ethanoic acid and ethanol were 0.42 mol dm^-3.

What is the concentration of ethyl ethanoate at equilibrium?

Ethyl Ethanoate Undergoes Following Reaction On The Picture Equal Amounts Of Ethanoic Acid And Ethanol Were Mixed Together And Allowed To Reach Equilibrium At E class=

Sagot :

Answer: The concentration of ethyl ethanoate at equilibrium is [tex]0.653mol/dm^3[/tex]

Explanation:

Given values:

Equilibrium concentration of ethanol = [tex]0.42mol/dm^3[/tex]

Equilibrium concentration of ethanoic acid = [tex]0.42mol/dm^3[/tex]

[tex]K_c=0.27[/tex]

The given chemical equation follows:

[tex]CH_3COOC_2H_5+H_2O\rightleftharpoons C_2H_5OH+CH_3COOH[/tex]

The expression of [tex]K_c[/tex] for above equation follows:

[tex]K_c=\frac{[C_2H_5OH][CH_3COOH]}{[CH_3COOC_2H_5]}[/tex]

Putting values in above expression, we get:

[tex]0.27=\frac{0.42\times 0.42}{[CH_3COOC_2H_5]}[/tex]

[tex][CH_3COOC_2H_5]=\frac{0.42\times 0.42}{0.27}=0.653mol/dm^3[/tex]

Hence, the concentration of ethyl ethanoate at equilibrium is [tex]0.653mol/dm^3[/tex]

cozzy04

Answer:

the answer is 0.81 mol/dm³

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