Answered

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Prove that: log b (p2 - q2) – log b (p + q) = log b (p – q)

Sagot :

sreedevi102

Answer:

Step-by-step explanation:

The formulas used to solve :

[tex][ log_b(\frac{x}{y}) = log_bx - log_by][/tex]

[tex](p^2 - q^2) = (p+q)(p-q)[/tex]

    [tex]log_b(p^2 - q^2) - log _b(p + q) = log_b(p-q)\\\\log_b(\frac{(p^2 -q^2)}{(p+q)}) = log_b(p-q)\\\\log_b(\frac{(p+q)(p-q)}{(p+q)}) = log_b(p-q)\\\\log_b(p-q) = log_b(p-q)\\\\[/tex]

Hence proved.

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