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Let h(x) = x*2 + kw - 8. If h(-1) = -5, what is the value of h(4)?
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Sagot :

sreedevi102

Answer:

h(4) = 0

Step-by-step explanation:

Hoping its ' kx '

[tex]h(x) = x^2 + kx -8 \\\\h(-1) = (-1)^2 + k(-1) - 8\\\\-5 = 1 - k -8\\\\-5 = -k -7\\\\-5 + 7 = -k\\\\2 = -k\\-2 = k[/tex]

Now we have k = -2. We will find h(4).

[tex]h(4) = (4)^2 + (-2)(4) - 8 = 16 -8 - 8 = 0[/tex]

Tekashii

Answer:

h(4) = 0

Step-by-step explanation:

GIVEN :-

  • A quadratic function h(x) = x² + kx - 8
  • h(-1) = -5

TO FIND :-

  • Value of h(4)

SOLUTION :-

To find the value of h(4) , you need to find 'k' first by using the given facts.

[tex]h(-1) = (-1)^2 + k(-1) - 8 = -5[/tex]

[tex]=> 1 - k - 8 = -5[/tex]

[tex]=> -k - 7 = -5[/tex]

  • Add both the sides by 7.

[tex]=> -k - 7 + 7 = -5 + 7[/tex]

[tex]=> -k = 2[/tex]

  • Multiply both the sides by -1.

[tex]=> -k(-1) = 2(-1)[/tex]

[tex]=> k = -2[/tex]

Putting the value of k,

[tex]h(4) = (4)^2 + (-2)(4) - 8[/tex]

       [tex]= 16 - 8 - 8[/tex]

       [tex]= 16 - 16[/tex]

       [tex]= 0[/tex]

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