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sreedevi102

Answer:

Step-by-step explanation:

[tex]\frac{a -30y}{a^2 -100y^2} - \frac{10y}{10ay -a^2}[/tex]

                               [tex]=\frac{a-30y}{a^2 -(10y)^2} - \frac{10y}{-a(a -10y)}\\\\=\frac{a-30y}{(a -10y)(a+10y)} + \frac{10y}{a(a -10y)}\\\\=\frac{a(a-30y) +10y(a+10y)}{a(a -10y)(a+10y)} \\\\=\frac{a^2 - 30ay +10ay +100y^2}{a(a-10y)(a+10y)}\\\\=\frac{a^2 - 20ay +100y^2}{a(a-10y)(a+10y)}\\\\=\frac{(a-10y)^2}{a(a-10y)(a+10y)}\\\\=\frac{(a-10y)}{a(a+10y)}[/tex]

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