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plz i need the answer

Plz I Need The Answer class=

Sagot :

sreedevi102

Answer:

x = 96

Step-by-step explanation:

[tex]log_b \ x = \frac{2}{3}log_b \ 27 + 3log_b \ 2 - log_b \ 3 + \frac{2}{3}log_b \ 64 - log_b \ 4[/tex]

         [tex]=\frac{2}{3}log_b \ 27 + 3log_b \ 2 + \frac{2}{3}log_b \ 64 -(log_b \ 3 + log_b \ 4) \\\\=(log_b \ (27)^{\frac{2}{3}} + log_b \ 2^3 + log_b \ (64)^{\frac{2}{3}}) -(log_b \ 3 + log_b \ 4) \\\\=log_b \ ( (27)^{\frac{2}{3}} \cdot 2^3 \cdot (64)^{\frac{2}{3}}) -log_b \ (3 \cdot 4) \\\\=log_b \ \frac{( (27)^{\frac{2}{3}} \cdot 2^3 \cdot (64)^{\frac{2}{3}})}{ (3 \cdot 4)} \\\\=log_b (\frac{9 \times 8 \times 16}{3 \times 4})\\\\=log_b (3 \times 8 \times 4)\\\\=log_b \ 96[/tex]

Therefore, x = 96

   

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