nataliaceciliad
Answered

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A skateboarder starts at 2.75 m/s and accelerates for 8.90 s over a distance of 16.7 m. What is his final velocity?

A) 3.44 m/s
B) 33.1 m/s
C) 1.00 m/s
D) 4.06 m/s

Sagot :

anhtampham

Explanation:

x = 16.7 m

v₀ = 2.75 m/s

t = 8.90 s

Find: v

x = ½ (v + v₀) t

16.7 m = ½ (v + 2.75 m/s) (8.90 s)

v = 1.00 m/s

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