ethanbaronkim
Answered

Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Ask your questions and receive precise answers from experienced professionals across different disciplines. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Will choose brainliest! How would you do this problem?

Will Choose Brainliest How Would You Do This Problem class=

Sagot :

Corsaquix

Answer:

[tex]c=8[/tex]

Step-by-step explanation:

When we plug in the solution [tex](x+2)[/tex], we will substitute [tex]x=-2[/tex], as [tex]-2+2=0[/tex].

To be divisible, a remainder of zero must be yielded.

Let's substitute [tex]x=-2[/tex] to see what we need to make [tex]c[/tex]:

[tex]p(-2)=4\cdot(-2)^3+c\cdot (-2)^2+(-2)+2,\\p(-2)=-32+4c[/tex]

Remember that we want a remainder of zero:

[tex]-32+4c=0,\\4c=32,\\c=\boxed{8}[/tex]

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.