ethanbaronkim
Answered

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Will choose brainliest! How would you do this problem?

Will Choose Brainliest How Would You Do This Problem class=

Sagot :

Corsaquix

Answer:

[tex]c=8[/tex]

Step-by-step explanation:

When we plug in the solution [tex](x+2)[/tex], we will substitute [tex]x=-2[/tex], as [tex]-2+2=0[/tex].

To be divisible, a remainder of zero must be yielded.

Let's substitute [tex]x=-2[/tex] to see what we need to make [tex]c[/tex]:

[tex]p(-2)=4\cdot(-2)^3+c\cdot (-2)^2+(-2)+2,\\p(-2)=-32+4c[/tex]

Remember that we want a remainder of zero:

[tex]-32+4c=0,\\4c=32,\\c=\boxed{8}[/tex]

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