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ankit1990

Answer:

answer is

[tex] \frac{6 {y}^{2} + 1}{2y} [/tex]

Step-by-step explanation:

since nothing is written under 3y, is denominator is 1.

in the other fraction denominator is 2y.

hence the 2 fractions are

[tex] \frac{3y}{1} \: and \: \frac{1}{2y} [/tex]

to write as a single fraction denominator should be common which will be the product of 1 and 2y which is 2y.

and the numerator should be cross multiplied. thus numerator is

[tex](3y \times 2y) + (1 \times 1) \\ = 6 {y}^{2} + 1[/tex]

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