Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

What's the inverse of ƒ(x) = x2 – 16?

Sagot :

the inverse of ƒ(x) = x²– 16

[tex] {f}^{ - 1} (x) = \sqrt{x + 16} [/tex]

View image Wallind123

Answer:

The inverse function should be f

[tex] {f}^{ - 1}( x) = \sqrt{x + 16} [/tex]

this is the correct answer