Answered

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.An ice cream vendor serves 4 flavors: vanilla, chocolate, strawberry, and mint. If the
vendor selects two flavors at random, what is the probability that vanilla and strawberry
are chosen?

Sagot :

Corsaquix

Answer:

[tex]\frac{1}{8}[/tex]

Step-by-step explanation:

This question may be relatively tricky. Since no specific order is stated or implied, it does not matter whether the vendor chooses vanilla or strawberry first, as long as the vendor chooses both.

Therefore, for the first flavor the vendor can either choose vanilla or strawberry. There is a [tex]\frac{2}{4}=\frac{1}{2}[/tex] chance of this happening.

For the second flavor, the vendor must choose the one they didn't pick for the first flavor (either strawberry or vanilla). There is a [tex]\frac{1}{4}[/tex] chance they do so.

Therefore, there is a [tex]\frac{1}{2}\cdot \frac{1}{4}=\boxed{\frac{1}{8}}[/tex] chance that vanilla and strawberry are chosen.

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