Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

The graph of a linear function passes through the
points (2, 11) and (6,21).
Write an equation for the function.
Use the number pad to enter numbers in the boxes.
y me
| x2 +


Sagot :

Answer:

y = 5/2x + 6

Step-by-step explanation:

Find the slope:

[tex]m=\frac{y_1-y_2}{x_1-x_2}\\\\m=\frac{11-21}{2-6}\\\\m=\frac{-10}{-4}\\\\m=\frac{5}{2}[/tex]

Use point-slope form to find the equation in slope-intercept form:

[tex]y-y_1=m(x-x_1)\\\\y-11=\frac{5}{2} (x-2)\\\\y-11=\frac{5}{2}x-5\\\\y=\frac{5}{2}x+6[/tex]