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5.96 g of ammonia reacts completely according to the following reaction:
2 NH3, (g) + Co2, (g) → CN2,OH4, (s) + H20 (l)
(a) What is the theoretical yield of urea (CN,OH,) for this reaction?
(b) If 13.74 g of urea are produced, what is the percent yield for this equation?

please show work, will give brainliest

Sagot :

unknown767

Explanation:

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khuranashilpa76

The theoretical yield of urea (CN, O, H,) for this reaction is = 9.88 g of urea

The percent yield for this equation is 176%

What is a chemical reaction?

A chemical reaction is a procedure in which one or more materials are transformed into one or extra unique materials. inside the response, the atoms of the beginning materials are rearranged, forming new substances which have specific residences.

calculation:-

2 NH3, (g) + Co2, (g) → CN2,OH4, (s) + H20 (l)

2*17 g of ammonia produces 60g of urea.

5.6 g of ammonia produces = (60/34)*5.6

                                               = 9.88 g of urea

60g of urea produced by 34 g of ammonia

  13.74 g of urea produced by =34/60*13.74

                                         = 7.78 g

percentage yield =  13.74 g of urea are produced/7.78

                            =1.76*100

                          ⇒ 176%

Learn more about percentage yield here:-https://brainly.com/question/25996347

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