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Graph a line that contains the point (-6,1) and has a slope of 5

Graph A Line That Contains The Point 61 And Has A Slope Of 5 class=

Sagot :

Answer:

Step-by-step explanation:

Equation of a line passing through a point (h, k) and slope 'm' is given by,

y - h = m(x - k)

Equation of a line passing through (-6, 1) and slope = 5,

y - 1 = 5(x + 6)

y = 5x + 31

Input-output values of the given equation,

x        -6              -4              -2              0                            

y          1               11              21             31              

Now plot these points on a graph.

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