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Find the limit of the function by using direct substitution Lim x-0(x^2+10)

Sagot :

9514 1404 393

Answer:

  10

Step-by-step explanation:

Maybe you want ...

  [tex]\displaystyle\lim_{x\to 0}(x^2+10)=0^2+10=\boxed{10}[/tex]