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Sagot :
Answer:
9 < √97 < 10
Step-by-step explanation:
√97 is a little less than √100
Which is 10
9 < √97 < 10
Answer: 9 < √97 < 10
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Explanation:
Consider that 81 < 97 < 100 is a true statement. Note the 81 and 100 are perfect squares such that 81 = 9^2 and 100 = 10^2
We can apply the square root to all three sides to get the following
[tex]81 < 97 < 100\\\\\sqrt{81} < \sqrt{97} < \sqrt{100}\\\\\sqrt{9^2} < \sqrt{97} < \sqrt{10^2}\\\\9 < \sqrt{97} < 10\\\\\text{The number }\sqrt{97} \text{ is between 9 and 10}\\\\[/tex]
Using a calculator, we can help verify this
[tex]\sqrt{97} \approx 9.85[/tex]
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