Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Please help me with this math

Please Help Me With This Math class=

Sagot :

aliya25

Answer:

(E) 9

Step-by-step explanation:

[tex]\frac{(3^{2008})^2-(3^{2006})^2}{(3^{2007})^2-(3^{2005})^2} = \\\frac{(3^{2007+1})^2-(3^{2007-1})^2}{(3^{2007})^2-(3^{2007-2})^2} = \\\frac{(3^{2007})^2(3^{2}-3^{-2} )}{(3^{2007})^2(1-3^{-4} )} =\\\frac{9-\frac{1}{9} }{1-\frac{1}{81} }=\\\frac{80}{9}:\frac{80}{81} = \\\frac{80}{9}*\frac{81}{80} = \frac{81}{9} = 9[/tex]

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.