Answered

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Compound A reacts with alcoholic KOH to yield compound B which on ozonolyzises followed by the reaction with Zn/H2O gives methanal and propanal Compound A is

Sagot :

Answer:

1-chlorobutane

Explanation:

Given that :

-- The compound A is made to react with alcoholic KOH and produce compound B.

-- The compound B on Ozonolysis produces methanol as well as propanol

The compound A should be a haloalkanes as treatment of haloalkanes with the alcoholic KOH, it will give alkene.

[tex]$CH_3CH_2CH_2CH_2Cl+KOH( \text{alcohol}) \rightarrow CH_3CH_2CH=CH_2+KCl+H_2O$[/tex]

So, the compound B should be Butene

Now the ozonolysis of the compound B or butene will give methanol and propanal as shown :

[tex]$CH_3CH_2CH=CH_2 \rightarrow CH_2O+CH_3CH_2CHO$[/tex]

Therefore, the compound A is 1-chlorobutane.

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