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Sagot :
Answer: [tex]15\ ft,6\ ft[/tex]
Step-by-step explanation:
Given
The area of a rectangular wall of a barn is [tex]135\ ft^2[/tex]
Suppose the width of the wall is [tex]x[/tex]
So, the length of the wall is [tex]6+x[/tex]
Area can be written as the product of length and width
[tex]\Rightarrow (6+x)x=135\\\Rightarrow 6x+x^2=135\\\Rightarrow x^2+6x-135=0\\\Rightarrow x=\dfrac{-6\pm \sqrt{6^2-4(1)(-135)}}{2(1)}\\\\\Rightarrow x=\dfrac{-6\pm 24}{2}\\\\\Rightarrow x=-15,9[/tex]
neglecting the negative value, width of the wall is [tex]9\ ft[/tex]
So, the length of the wall is [tex]9+6=15\ ft[/tex]
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