Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

From the sample space S=(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15) a single number is to be selected at random. Given event A, that the selected number is even, and event B, that the selected number is a multiple of 4, find P(AIB)​

Sagot :

MrRoyal

Answer:

[tex]P(A|B) = 1[/tex]

Step-by-step explanation:

Given

[tex]S = \{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15\}[/tex]

[tex]A = \{2,4,6,8,10,12,14\}[/tex]

[tex]P(A) = 7/15[/tex]

[tex]B = \{4,8,12\}[/tex]

[tex]P(B) = 3/15[/tex]

Required

[tex]P(A|B)[/tex]

This is calculated as:

[tex]P(A|B) = \frac{P(A\ n\ B)}{P(B)}[/tex]

Where

[tex]A\ n\ B = \{4,8,12\}[/tex]

[tex]P(A\ n\ B) = 3/15[/tex]

So, we have:

[tex]P(A|B) = \frac{P(A\ n\ B)}{P(B)}[/tex]

[tex]P(A|B) = \frac{3/15}{3/15}[/tex]

[tex]P(A|B) = 1[/tex]

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.