Answered

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In ΔFGH, the measure of ∠H=90°, FH = 8, OF = 17, and HG = 15. What ratio represents the sine of ∠G?

Sagot :

MrRoyal

Answer:

[tex]\sin(G) = \frac{8}{17}[/tex]

Step-by-step explanation:

Given

[tex]\angle H = 90^o[/tex]

[tex]FH = 8[/tex]

[tex]GF = 17[/tex]

[tex]HG = 15[/tex]

See attachment for illustration

Required

The ratio of [tex]\sin(G)[/tex]

[tex]\sin(G)[/tex] is calculated as:

[tex]\sin(G) = \frac{Opposite}{Hypotenuse}[/tex]

From the attachment, we have:

[tex]\sin(G) = \frac{FH}{GF}[/tex]

This gives:

[tex]\sin(G) = \frac{8}{17}[/tex]

View image MrRoyal
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