Answered

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An unknown substance weighing 42.0 g was heated from 36.0°C to 65.0°C. In this process, the
substance absorbed 5895 J of energy. What is the specific heat of the substance?

A. 5895 J/(g*C)
B. 4.18 J/(g*C)
C. 4.84 J/( g*C)
D. O.06 J/(g*C)

Sagot :

priya151255

Answer:

A. 5895 J/g*C)

Explanation:

An unknown substance weighing 42.0 g was heated from 36.0°C to 65.0°C. In this process, the substance absorbed 5895 J of energy.

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