Answer:
[tex]h^{-1}(x) = \frac{4}{3}x + \frac{23}{3}[/tex]
Step-by-step explanation:
Given
Graph h:
[tex](x_1,y_1) = (1,-5)[/tex]
[tex](x_2,y_2) = (9,1)[/tex]
Required
Plot [tex]h^{-1}(x)[/tex]
First, calculate h(x)
Calculate slope (m)
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
[tex]m = \frac{1--5}{9-1}[/tex]
[tex]m = \frac{6}{8}[/tex]
[tex]m = \frac{3}{4}[/tex]
The equation is:
[tex]y = m(x - x_1) + y_1[/tex]
So, we have:
[tex]y = \frac{3}{4}(x - 1) -5[/tex]
[tex]y = \frac{3}{4}x - \frac{3}{4} -5[/tex]
[tex]y = \frac{3}{4}x + \frac{-3 - 20}{4}[/tex]
[tex]y = \frac{3}{4}x - \frac{23}{4}[/tex]
Next, calculate [tex]h^{-1}(x)[/tex]
Swap y and x
[tex]x = \frac{3}{4}y - \frac{23}{4}[/tex]
Solve for y
[tex]\frac{3}{4}y = x + \frac{23}{4}[/tex]
Multiply through by 4
[tex]3y = 4x + 23[/tex]
Divide through by 3
[tex]y = \frac{4}{3}x + \frac{23}{3}[/tex]
Replace y with [tex]h^{-1}(x)[/tex]
[tex]h^{-1}(x) = \frac{4}{3}x + \frac{23}{3}[/tex]
See attachment for graph
