Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

What is the reduction half-reaction for the equation below?
5Fe2+(aq) + MnO4" (aq) + 8H+(aq) → 5Fe3+ (aq) + Mn2+(aq) +
4H2O(1)

Sagot :

sebassandin

Answer:

[tex]MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O[/tex]

Explanation:

Hello there!

In this case, since redox reactions are characterized by the presence of a reduction reaction, whereby the oxidation of the element decreases, and an oxidation reaction whereby the oxidation of the element increases.

In such a way, for the given chemical equation, we can see Fe is increasing its oxidation state from 2+ to 3+, which means it is oxidized. On the flip side, Mn is being reduced from 7+ (MnO₄⁻) to 2+ and this, the reduction half-reaction is:

[tex]MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O[/tex]

Whereas five electrons are carried.

Regards!

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.