kunni2716
Answered

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pls help me on this i don't know what to do ​

Pls Help Me On This I Dont Know What To Do class=

Sagot :

pc192y

Answer:

D.

Step-by-step explanation:

Standard Form (Quadratic): [tex]y=ax^2+bx+c[/tex]

Vertex Form (Quadratic): [tex]y=a(x-h)^2+k[/tex]

Intercept Form (Quadratic): [tex]y=a(x-p)(x-q)[/tex]

      p,q are x-intercepts

x-intercepts given in graph: -2,4

[tex]y=a[x-(-2)](x-4)[/tex]

eqn 1: [tex]y=a(x+2)(x-4)[/tex]

Plug in the given point to find 'a' : (3,-5)

[tex]-5=a(3+2)(3-4)[/tex]

[tex]-5=a(5)(-1)[/tex]

[tex]1=a[/tex]

Substitute 'a' in to eqn 1.

[tex]y=1(x+2)(x-4)[/tex]

eqn 2: [tex]y=(x+2)(x-4)[/tex]

Expand eqn 2. (can use FOIL)

[tex]y=x^2-2x-8[/tex]

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