Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Answer:
Explanation:
This is an exercise in kinematics, the speed they give is in two dimensions, let's work on each component
X axis
initial velocity v₀ₓ = 3 m / s in a time of t = 12 s, the velocity is doubled, the final velocity is vₓ = 6 m / s
acceleration is
vₓ = v₀ₓ + aₓ t
aₓ = [tex]\frac{v_x - v_{ox}} {t}[/tex]
aₓ = 6 - 3/12
aₓ = 0.25 m / s²
the distance traveled is
vₓ² = v₀ₓ² + 2 aₓx x
x = vx² - vox² / 2a
x = 6² - 3² / 2 0.25
x = 54 m
Y axis
we look for acceleration
v_y = v_{oy} + a_y t
a_y = [tex]\frac{v_y - v_{oy} }{t}[/tex]
a_y = [tex]\frac{8 -4} {12}[/tex]
ay = 0.3333 m / s²
the distance is
v_y² = v_{oy}² + 2 a⁷y
y = vy² - voy² / 2 0.25
y = 8² - 4² / 2 0/3333
y = 72 m
the distance traveled is
r = (54 i + 72j) m / s
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.