Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Volume of square based pyramid is 1568 cm3 and half of the length of the

side of the base is 7cm. Calculate the area of triangular faces of pyramid.
​

Sagot :

redgram

answer:

1393.84

Step-by-step explanation:

since the formula for a square base pyramid is a^2×h/3

we can find out the height for the pyramid by dividing the a^2×h/3 by a^2 =h/3

1568/7^2=32 since 32 = h/3 we multiply by 3 to find the height which = 96

now that we have the height we usee the pathagorean Therom to find the height of one of the face triangles

so 96^2+3.5^2=L^2 so L =96.06

so now that we have all we need

the surface area of the square at the bottom of the pyramid is 7×7

the surface area of the triangles are 96.06 ×7/2 since the area of a triangle is h×b/2

since there are 4 triangles and on square 49+4(96.06×7/2)= 1393.84

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.