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if the angles (4x+4) and 6x-4 are supplement Ary angles find value of x plzz helppp​

Sagot :

[tex] \huge \star[/tex] Given :

Angles (4x + 4°) and (6x - 4°) are supplementary.

That is :

  • [tex](4x + 4°) + (6x - 4°) = 180°[/tex]

Solution :

[tex]\hookrightarrow \: 4x + 4 \degree + 6x -4 \degree = 180 \degree[/tex]

[tex]\hookrightarrow10x = 180 \degree[/tex]

[tex]\hookrightarrow x = 18 \degree[/tex]

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