dheepty0103
Answered

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For the equation y=2x + 6, find the value of y when
(a) x= 0 (b) x= 1
(c) x=2 (d) x=3

WITH CALCULATION AND EXPLANATION PLEASE.FULL CALCULATION

Sagot :

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \huge \mathrm{ \underbrace{Answer}}[/tex]

The given equation is :

[tex] \huge \boxed{ y = 2x + 6 }[/tex]

Now, let's solve for each value of "x"

[tex]\mathrm {\hookrightarrow \:1. \: \: when \: \: x = 0}[/tex]

  • [tex]y = 2x + 6[/tex]
  • [tex]y = (2 \times 0) + 6[/tex]
  • [tex]y = 6[/tex]

[tex]\mathrm{\hookrightarrow 2.\: \: when \: \: x = 1}[/tex]

  • [tex]y = 2x + 6[/tex]
  • [tex]y = (2 \times 1) + 6[/tex]
  • [tex]y = 2 + 6[/tex]
  • [tex]y = 8[/tex]

[tex]\mathrm {\hookrightarrow \: 3. \: \: when \: \: x = 2}[/tex]

  • [tex]y = 2x + 6[/tex]
  • [tex]y = (2 \times 2) + 6[/tex]
  • [tex]y = 4 + 6[/tex]
  • [tex]y = 10[/tex]

[tex]\mathrm{\hookrightarrow \: 4. \: \: when \: \: x = 3}[/tex]

  • [tex]y = 2x + 6[/tex]
  • [tex]y = (2 \times 3) + 6[/tex]
  • [tex]y = 6 + 6[/tex]
  • [tex]y = 12[/tex]

[tex] \mathrm{✌TeeNForeveR✌}[/tex]

blackshades

Answer:

[tex]\huge\boxed{Answer\hookleftarrow}[/tex]

Equation = [tex]\large\bold{y = 2x + 6}[/tex]

a) [tex]x = 0[/tex]

Substitute the value of x as 0 in the equation.

[tex]y = 2x + 6 \\ y = 2(0) + 6 \\ y = 0 + 6 \\ y = 6[/tex]

✐ Answer of a) is [tex]\large\bold{y = 6}[/tex]

____________________

b) [tex]x = 1[/tex]

Substitute the value of x as 1 in the equation.

[tex]y = 2x + 6 \\ y = 2(1) + 6 \\ y = 2 + 6 \\ y = 8[/tex]

✐ Answer of b) is [tex]\large\bold{y = 8}[/tex]

____________________

c) [tex]x = 2[/tex]

Substitute the value of x as 2 in the equation.

[tex]y = 2x + 6 \\ y = 2(2) + 6 \\ y = 4 + 6 \\ y = 10[/tex]

✐ Answer of b) is [tex]\large\bold{y = 10}[/tex]

____________________

d) [tex]x = 3[/tex]

Substitute the value of x as 3 in the equation.

[tex]y = 2x + 6 \\ y = 2(3) + 6 \\ y = 6 + 6 \\ y = 12[/tex]

✐ Answer of d) is [tex]\large\bold{y = 12}[/tex]

____________________

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

# ꧁❣ RainbowSalt2²2² ࿐

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