menyahcyril
Answered

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Two containers, A and B begin with equal volumes of liquid.
120 ml is then poured from A to B.
А
B
Container B now contains 4 times as much liquid as A.
Find the volume of liquid left in container A at the end.
A
A
B.
B
Volume left in container A=
20
ml

Sagot :

ankit1990

Answer:

volume left in A is 80ml

Step-by-step explanation:

let original volume in both be x ml

after pouring from A to B

vol in A = x - 120

vol in B = x + 120

now it is given that

vol in B = 4 times vol in A

implies

[tex]x + 120 = 4 \times (x - 120) \\ x + 120 = 4x - 480 \\ 3x = 600 \\ x = 200[/tex]

hence original volume in A is 200ml. after pouring in B it is 200-120 = 80 ml

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