Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

PLEASE HELP ME WITH THIS ONE QUESTION
The color orange has a wavelength of 590 nm. What is the energy of an orange photon? (h = 6.626 x 10^-19, 1 eV = 1.6 x 10^-19 J)

A) 2.81 eV

B) 3.89 eV

C) 2.10 eV

D) 2.78 eV

Sagot :

SOFlA

k = [tex] \dfrac{ (\dfrac{h}{ \lambda} )^{2} }{2m} [/tex]

k = (6.626×10-¹⁹/590 × 10-⁹ )^{2} /2 × 1.673 × 10-²⁷

k = (1.12 × 10-³⁰)^2/3.346×10-²⁷

k = 1.25 × 10-⁶⁰ /3.346×10-²⁷

k = 0

ldk why, my answer is coming this :(

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.