aeri1485
Answered

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If (x+y)^2=125xy,
show that, 2 log (x+y) = 3 log 5+log x+ log y​

Sagot :

sreedevi102

Formulas used :

[tex]loga^ x = x \ log a[/tex]

[tex]logab = log a + logb[/tex]

Steps :

[tex](x+y)^2 = 125xy\\\\log(x+y)^2 = log(125xy)\\\\2log(x+y) = log 125 + log x + log y\\\\2log(x+y) = log 5^3+ log x + log y\\\\2log(x+y) = 3 log 5 + log x + log y\\\\[/tex]

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