Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

please help
it would mean the
absolute world:/ giving away lots of points:/

Please Help It Would Mean The Absolute World Giving Away Lots Of Points class=

Sagot :

sreedevi102

Answer:

:)

Step-by-step explanation:

[tex]M = 3x^2y^3-4xy +x^3y\\\\2M = 2 \times (3x^2y^3-4xy +x^3y) \\\\[/tex]

      [tex]= 6x^2y^3 - 8xy + 2x^3y[/tex]

[tex]N = -2x^3y + 6x^2y^3 -8xy -8[/tex]

   [tex]= 6x^2y^3 -8xy -2x^3y -8[/tex]                 [tex][ re-arranging \ the \ terms][/tex]

a)

[tex]2 M - N = ( 6x^2y^3 -8xy +2x^3y) - (6x^2y^3-8xy -2x^3y - 8)[/tex]

            [tex]= 6x^2y^3 - 8xy +2x^3y -6x^2y^3 +8xy +2x^3y + 8\\\\= 4x^3y +8[/tex]

b)

[tex]2M - N \ for \ x = -1 \ and \ y = 2: (4(-1)^3\times (2)) + 8 = -8 + 8 = 0[/tex]

         

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.