Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

please help
it would mean the
absolute world:/ giving away lots of points:/

Please Help It Would Mean The Absolute World Giving Away Lots Of Points class=

Sagot :

Answer:

:)

Step-by-step explanation:

[tex]M = 3x^2y^3-4xy +x^3y\\\\2M = 2 \times (3x^2y^3-4xy +x^3y) \\\\[/tex]

      [tex]= 6x^2y^3 - 8xy + 2x^3y[/tex]

[tex]N = -2x^3y + 6x^2y^3 -8xy -8[/tex]

   [tex]= 6x^2y^3 -8xy -2x^3y -8[/tex]                 [tex][ re-arranging \ the \ terms][/tex]

a)

[tex]2 M - N = ( 6x^2y^3 -8xy +2x^3y) - (6x^2y^3-8xy -2x^3y - 8)[/tex]

            [tex]= 6x^2y^3 - 8xy +2x^3y -6x^2y^3 +8xy +2x^3y + 8\\\\= 4x^3y +8[/tex]

b)

[tex]2M - N \ for \ x = -1 \ and \ y = 2: (4(-1)^3\times (2)) + 8 = -8 + 8 = 0[/tex]