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Sagot :
Answer:
[tex]5[/tex]
Step-by-step explanation:
[tex](2−i)(2+i)[/tex]
[tex]2(2+i)−i(2+i)\\ 2⋅2+2i−i(2+i) \\2⋅2+2i−i⋅2−ii[/tex]
[tex]4+2i−2i \\ 5+2i−2i \\ 5+0 \\ 5[/tex]
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