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factorise fully 16c^4p^2+20cp^3​

Sagot :

bhadelsimron19

Answer:

Step-by-step explanation:

16c^4p^2 + 20cp^3

take common

=4cp^2(4c^3 + 5p)

VectorFundament120

Given the expression below:

[tex] \large \boxed{16 {c}^{4} {p}^{2} + 20c {p}^{3} }[/tex]

We can factor out c-term, p² and 4 (from 16 and 20)

[tex] \large{4c {p}^{2} (4 {c}^{3} + 5p)}[/tex]

Answer

  • 4cp²(4c³+5p)

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