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If one point on a graph is (5,5) and the slope of the line is -4, write the equation of the line in slope-
intercept form.

Sagot :

Answer:

y = -4x + 25

Step-by-step explanation:

[tex](x_1, y_1) = (5, 5) \ ; \ slope ,\ m = -4[/tex]

Equation of line :

 [tex](y - y_1) = m(x - x_1)[/tex]

 [tex](y - 5) = -4(x-5)\\y - 5 = -4x + 20\\y = -4x +20 + 5\\y = -4x + 25[/tex]

Answer:

0=4x+y-5

Step-by-step explanation:

slope(m)=-4

y-intercept(c)=5

now, the equation joining the straight line satisfy the equation,

y=mx+c

or, y= -4x+5

or, 4x+y-5=0

or, 0=4x+y-5

it is the required equation.